(18x^2+27x+13)=(3x+3)

Solution for (18x^2+27x+13)=(3x+3) equation:

(18x^2+27x+13)=(3x+3)

We move all terms to the left:

(18x^2+27x+13)-((3x+3))=0

We get rid of parentheses

18x^2+27x-((3x+3))+13=0


We calculate terms in parentheses: -((3x+3)), so:

(3x+3)

We get rid of parentheses

3x+3

Back to the equation:

-(3x+3)


We get rid of parentheses

18x^2+27x-3x-3+13=0

We add all the numbers together, and all the variables

18x^2+24x+10=0

a = 18; b = 24; c = +10;
Δ = b2-4ac
Δ = 242-4·18·10
Δ = -144
Delta is less than zero, so there is no solution for the equation